A restaurant offers a special pizza with any 4 toppings. If the restaurant has 15 topping from which to choose, how many different special pizzas are possible.

Using the combination principle, the number of special pizzas from which to choose from is 1365

Using Combination :

nCr = [(n! ÷ (n - r)! r!)]

15C4 = [(15! ÷ (15 - 4)! 4!)]

15C4 = [(15! ÷ 11!4!)]

15C4 = (15 × 14 × 13 × 12) ÷ (4 × 3 × 2 × 1)

15C4 = 32760 / 24

15C4 = 1365

Therefore, 1365 different special pizzas can be made.

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1,365 possible special pizzas

Step-by-step explanation:

For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.

15 * 14 * 13 * 12 = 32,760

Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.

4 * 3 * 2 * 1 = 24

32,760 / 24 = 1,365

There are 1,365 possible special pizzas

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb