The times for completing one circuit of a bicycle course are normally distributed with a mean of 72.5 minutes and a standard deviation of 6.5 minutes. An association
wants to sponsor a race but will eliminate the bottom 75% of riders. In a trial run,
what should be the cutoff time?

The answer is 76.9 rounded or rounds.

Step-by-step explanation:

Solution

Given that:

Mean = μ = 72.5

Standard deviation = σ = 6.5

Now

By applying the standard normal table we have the following:

P(Z < z) = 75%

= P(Z < z)

= 0.75

Thus

z =0.67 by using the standard normal z table

Applying the  z-score formula we have:

x = z * σ + μ

x = 0.67*6.5+72.5

x= 76.855 ≈ 76.9

Therefore the cutoff time is 76.9 rounds.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without