If you help me i will mark brainliest

C. 39.3 inches^2

In order to solve this, you will need to know the formulas to find the area of a triangle, rectangle, and circle.
You can divide the pentagon into a triangle and rectangle, keeping the half circle on the side as a half circle.
The area of the rectangle would be length times width (4 x 6 = 24 inches^2). The area of the circle would be 3.14 times the radius squared, since we are given the diameter of the half circle, we divide the diameter by 2 to get the radius of 2 (4/2 = 2). Then you find the area of the circle (3.14 x 2^2) and divide the area by half since it is only a half circle (12.56/2 = 6.28 inches^2). Now you find the area of the triangle which is base times height divided by 2. You subtract 4 inches (height of rectangle) from the height of the entire pentagon to get you the height of the triangle which would be 3 inches, with a base of 6 inches (6 x 3 = 18, 18/2 = 9 inches^2). Now you add together the area of the circle, triangle, and rectangle to get 39.28 inches^2 and when you round that number to the tenths place, you get C. 39.28 inches^2 as your answer.

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