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0.6 - 1/4

Convert the decimal to fraction

Thus

0.6 = 3/4

3/5 - 1/4

Find the LCM

the LCM is 20

We get

3/5 - 1/4 = (3(4) - 5)/ 20

= 12-5/20

= 7/20

2/5 + 0.75

0.75 = 3/4

Find the LCM

The LCM is 20

Thus

3/4 +2/5 = ( 3(5) + 2(4))/20

= 15 + 8 /20

= 23 / 20 or 1 3/20

1.75 - 1/6

Convert the decimal to fraction

1.75 = 7/4

Thus we get

7/4 - 1/6

Find the LCM

The LCM is 12

Thus

7/4 - 1/6 = ( 7(3) - 2)/12

= 21 - 2 / 12

= 19/ 12 or 1 7/12

3/10 + 2.125

Convert the decimal to fraction

2.125 = 17/8

Thus

3/10 + 17/8

Find the LCM

the LCM is 40

Thus

3/10 + 17/8 = ( 3(4) + 17(5))/40

= 12 + 85/40

= 97 /40 or 2 17/40

Hope this helps

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation: