A business school professor is interested to know if watching a video about the Central Limit Theorem To assess this, the professor tests students knovwledge both immediately helps students understand it. before they watch the video and immediately after The professor takes a sample of students, and for each one compares their test score after the videb to their score before the video Using the data below calculate the p-value for the following hvpothesis test:. H0:μafter≤μbeforeHa:μafter>μbefo reStudent Test score before Student Test Sscore after Student ID 78.4 83.6 5462 63 5 46.6 71.4 3829 51.5 1342 4 76 4 67 4 57.9 6538 7739 76 1 73.4 5668 53 5 65.6 7 713 2208 64.8 73.3 573 5087 748 9305 56 4 9557 76 8 0684 68.5 57.5 54 4 2596 66.4 4344 7546 73.4 62.0 68.0 64 4 69.7 7392 59.6 8121 55 2 56.6 8249 83.4 56 6 5351 KET 2199%99N99.

konichiwa~! my name is zalgo and i am here to answer your anime-related question today. more than likely, kirishima would kill izuku, marry mino and kiss momo. all of this would be my opinion by the way. (and i am also a weeb lol)

i hope this you! : d

stay and stay proud! " - zalgo

(and do you think you can mark me as brainliest? i'd greatly appreciate it! arigato~! )

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

.95

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.