A standard deck of cards contains 52 cards. One card is selected from the deck. (a) Compute the probability of randomly selecting a diamond or club. (b) Compute the probability of randomly selecting a diamond or club or heart. (c) Compute the probability of randomly selecting a three or club.

To solve the questions we must know the concept of Probability.

The probability helps us to know the chances of an event occurring.

Explanations

(a) Compute the probability of randomly selecting a diamond or club.

The number of diamond cards = 13

The number of club cards = 13

The total number of diamond and club cards = 26

(b) Compute the probability of randomly selecting a diamond or club or heart.

The number of diamond cards = 13

The number of club cards = 13

The number of heart cards = 13

The total number of diamond, heart, and club cards = 39

(c) Compute the probability of randomly selecting a three or club.

The number of three cards = 4

The number of club cards = 13

The total number of diamond and club cards = 13+4 - 1 =16

we reduced a card because card three of the club is calculated twice.

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Ok, in a deck of 52 cards we have:

13 clubs, 13 diamonds, 13 hearts, and 13 spades.

For this problem, we assume that the probability of selecting a card at random is the same for all the cards,  so each card has a  probability of 1/52 of being selected.

then the probability of drawing a given outcome, is equal to the number of times that the outcome appears in the deck divided the number of cards.

a) probability of randomly selecting a diamond or club.

in the 52 cards deck, we have 13 diamonds and 13 clubs, so the probability of drawing a diamond or a club is equal to:

P = (13 + 13)/52 = 26/52 = 0.5

b) Compute the probability of randomly selecting a diamond or club or heart.

Same reasoning as before, here we have 13 + 13 + 13 = 39 possible options, so the probability is:

p = 39/52 = 0.75.

c)  Compute the probability of randomly selecting a three or club.

we have 13 club cards, and in the deck, each number appears 4 times, so we have 4 cards with a number 3 on them.

But one of those 3's is also a club card, so we already counted it in the 13 club cards, then the number of possible options here is:

13 + 4 - 1 = 13 +3 = 16

then the probability is:

p = 16/52 = 0.31

practice. practice. practice.