Tin of biscuits come in three sizes. There are 28 biscuits in a small size and four times as many in the medium size. In the large size there are seven times as many as in small size how many biscuits are in the small and large size

There are 28 biscuits in a small size.

There are 112 biscuits in a medium size.

There are 196 biscuits in a large size.

Step-by-step explanation:

Tin of biscuits come in three sizes:

Let S denote biscuits in small size.

Let M denote biscuits in medium size.

Let L denote biscuits in large size.

There are 28 biscuits in a small size and four times as many in the medium size.

Mathematically,

S = 28

M = 4S

Substitute S = 28

M = 4(28)

M = 112

In the large size there are seven times as many as in small size.

L = 7S

Substitute S = 28

L = 7(28)

L = 196

Therefore,

There are 28 biscuits in a small size.

There are 112 biscuits in a medium size.

There are 196 biscuits in a large size.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;