An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and located directly above a tower (1). The observer also notices a

bird (B) circling directly above her. If the distance from the plane(P) to the tower () is 7,000 feet,

how far is the bird (B) from the plane (P)? Round to the nearest whole number.

B

х

P

7000

1

1

1

33°

A

10,779 feets

Step-by-step explanation:

From the sketch attached ;

∠POT is the Angle of elevation = 33°

Height of tower = 7000 Feets

Taking the triangle POT

WHERE PT = 7000 Feets (Opposite)

Distance (d) between the bird and plane is the ADJACENT,

NOTE: (BP = OT = d)

Taking the tangent of the angle of elevation;

Tan Θ = opposite / Adjacent

Tan 33° = 7000 / d

Cross multiply

d × 0.6494075 = 7000

d = 7000 / 0.6494075

d = 10779.054 = 10,779 feets

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

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