For each sequence, find the first 4 terms and the 10th term. a) 12-n
b) 5 - 2n
c) n^2+3
d) 2n^2

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Step-by-step explanation:

Sequence (a),

Recursive formula of given sequence has been given as,

T(n) = 12 - n

First 4 terms of the sequence will be,

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

And 10th term of the sequence will be,

T(10) = 12 - 10 = 2

Sequence (b),

Recursive formula is,

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

Sequence (c),

Recursive formula is,

T(n) = n² + 3

T(1) = 4

T(2) = 7

T(3) = 12

T(4) = 19

T(10) = 103

Sequence (d),

Recursive formula,

T(n) = 2n²

T(1) = 2

T(2) = 8

T(3) = 18

T(4) = 32

T(10) = 200

what's the question?

step-by-step explanation:

there is no question.