You find 20 coins consisting only of nickels, dimes, and quarters, with a face value of $2.65. However, the coins all date from 1929, and are worth considerably more than their face value. A coin dealer offers you $7 for each nickel, $5 for each dime, and $20 for each quarter, for a total of $221. How many of each type of coin did you find

8 nickels, 5 dimes and 7 quarters

Step-by-step explanation:

Each nickel is $0.05, each dime is $0.10 and each quarter is $0.25.

So, if we have n nickes, d dimes and q quarters, we can write the system of equations:

If we multiply (eq2) by 140 and (eq1) by 7, we have:

Now, making (eq4) - (eq3) and (eq5) - (eq3), we have:

Multiplying (eq7) by 4.5, we have:

Subtracting (eq6) by (eq8), we have:

Finding 'd' using (eq6), we have:

Finding 'n' using (eq1), we have:

So we have 8 nickels, 5 dimes and 7 quarters.

a = 11 : 4

b = 38

c = 1 for every 6

understand that i don't know the answers

will someone answer his question