The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2. Obi spent £20 that day. Obi now had £8 less than Rudy. How much did they have initially altogether?

Initially, they have £28 altogether

Step-by-step explanation:

Obi: Rudy=5:2

this means that Obi had 5x and Rudy has 2x in their wallets.

Obi spent £20 and 5x-20 left. Obi now had £8 less than Rudy

thus,

2x-(5x-20) =8

2x-5x+20=8

-3x=-12

x=4

obi =5x

=5*4

=20

Rudy =2x

=2*4

=8

This means that initially Obi had £20 and Rudy had £8

Total if Rudy and obi

=£8+£20

=£28

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)