What is the solution to the system of the equation. Please help me.

x=3, y=2

Step-by-step explanation:

since y =2x-4, we name it as equation I

and the second system as equation 2.

we substitute equation 1 into 2 and we have;

4x+3(2x-4)=18

4x+6x-12=18

10x=18+12

x= 30÷10

x=3.

now, substituting x=3 into the y equation , we have

y= 2(3)-4

y=2.

therefore, x=3, y=2.

...if I was to plot this I would use the equation intercepts. Some people might use the slope whichever is okay for you. but I like to use the intercepts...(x,y)

so first, to find the intercept of equation 1;

we have,

y=2x-4

we set x= 0 and we get .y=2(0)-4=-4, we have (0,-4)...x=0, y=-4 for intercept

we set y to 0 to get the intercept for x...

we have, 0=2x-4=2..we get (2,0)...x=2, y=0 for the second intercept.

we do same for the second equation...

4x+3y=18...

so when doing this set x to 0 to get y intercept that is (0,y) and set y= 0 to get the x intercept that is (x,0)... then you can plot the points on your graph...

the intercept of the two system after you've plotted it on your graph should give you the solution we have that is x=3, y=2.

x+14

step-by-step explanation: