Fewer young people are driving. In 1983, of -year-olds had a driver's license. Twenty-five years later that percentage had dropped to 75% (University of Michigan Transportation Research Institute website, April 7, 2012). Suppose these results are based on a random sample of -year-olds in 1983 and again in 2008. Requried:
a. At 95% confidence, what is the margin of error and the interval estimate of the number of 19 years old drivers in 1983?
b. At 95% confidence, what is the margin of error and the interval estimate of the number of 19 years old drivers in 2008?
c. Is the margin of error is same in part (a) and (b).

a) MOE = 0.0190

b) MOE = 0.0245

c) No, because the margin of error depends on the standard error, and the later depends on the proportion. The closer the proportion to 0.5, the larger the standard error (for equal sample size).

Step-by-step explanation:

The question is incomplete:

Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver's license. Twenty-five years later that percentage had dropped to 75% (University of Michigan Transportation Research Institute website, April 7, 2012). Suppose these results are based on a random sample of  1200 19-year-olds in 1983 and again in 2008.

a) The sample proportion is p=0.87.

The standard error of the proportion is:

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

b) The sample proportion is p=0.75.

The standard error of the proportion is:

The critical z-value for a 95% confidence interval is, as in point a, z=1.96.

The margin of error (MOE) can be calculated as:

c) No, because the margin of error depends on the standard error, and the later depends on the proportion. The closer the proportion to 0.5, the larger the standard error (for equal sample size).

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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