What is the equation of the line that goes through (2, -1) and is parallel to y=
3x - 3?

y + 1 = 3 (x - 2) (the first option - A - in the list of possible answers)

Step-by-step explanation:

Since the new line has to be parallel to y = 3 x - 3, then it has to have the SAME slope (3) and go through (2, -1). Therefore the slope-point general form has to be:

y - (-1) = 3 (x - 2)

y + 1 = 3 (x - 2)

Which is the first option in the list of possible answers

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

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step-by-step explanation:

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