If bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options. m∠ABC = 125° and AB ≅ DB ΔACD is isosceles with base AD ΔABD is isosceles with base AD CD = 52 cm AB = 29 cm

A) m∠ABC = 125° and AB ≅ DB ; B) ΔACD is isosceles with base AD ; D) CD = 52 cm.

Step-by-step explanation:

see attachment for the missing figure.

On the off chance that we knew the proportion of ∠ABC and realized that AB ≅ DB, we would have either ASA (edge side-angle) or SAS (side-angle side). This is on the grounds that we know since CB cuts up ∠ACD, ∠ACB is congruent to ∠DCB. Accordingly we have two angles with a side between them or different sides with an angle between them.

On the off chance that we realize that ΔACD is isosceles with base AD, this implies AC is congruent to DC. This implies we have two sides with a point between the, or SAS.

On the off chance that we realize that CD = 52 cm, this implies AC and CD are congruent. This gives us different sides with an included point, or SAS.

3,000,540

step-by-step explanation: