Set up the characteristic equation, which is given by r2 − 5r − 6 = 0. The roots of this equation are given by r1 = 6 and r2 = −1. Thus a general solution for the recurrence is given by an = a6 n + b(−1)n . To find a and b, we use the initial conditions. a0 = 1 implies a + b = 1, while a1 = 3 implies 6a − b = 3.

Step-by-step explanation:

From your characteristic equation, your recursive equation is

the general solution:

The initial conditions are

For f(0) = 1, that is

For f(1) = 3, that is

From (*) and (**) you solve for A and B

you have A = 4/7 and B= 3/7

Replace A, B into the general one, you have the particular solution for the given condition

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

answer: i feel you honey.

step-by-step explanation: