Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference of the two grades is 16. The sum of one-eighth of the higher grade and one-half of the lower grade is 52. The system that represents his scores is below. x – y = 16 StartFraction 1 over 8 EndFraction x plus StartFraction one-half EndFraction y equals 52.x + StartFraction one-half EndFraction x plus StartFraction one-half EndFraction y equals 18.y = 52 What is the higher grade of Jose’s two tests?

Answer : 96

x – y = 16 > equation 1

1/8 x + 1/2 y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

1/8 x + 1/2 ( -16 + x ) = 52

1/8x - 8 + 1/2 x = 52

1/8x + 1/2x - 8 = 52

Take common denominator to combine fractions

1/8x + 4/8x -8 = 52

5/8x - 8 = 52

Add 8 on both sides

5/8x = 60

Multiply both sides by 8/5

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

It is not C, nor is it B. The only Logical answer is D, 96.

Step-by-step explanation:

I hope this helps you on your academical endeavors!!

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step-by-step explanation:

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of