Which equation correctly uses the law of cosines to solve for the length s?
92 = 52 + 102 - 2(s)(10) cos(100°)
9 = s + 10 - 2(s)(10)cos(100)
102 = 52 + 100 – 2(s)(10)cos(100)
S2 = 92 + 102 - 2(9)(10)cos(100)

fourth option

Step-by-step explanation:

Using the Law of Cosines in Δ STU to find s

s² = t² + u² - 2us cosS

where t = 9, u = 10 and S = 100° , thus

s² = 9² + 10² - 2(9)(10)cos100°

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