Scenario: A corporation randomly selects 150 sales people and finds that 66% who have never taken a self-improvement course would like such a course. The firm did a similar study 10 years ago in which 60% of a random sample of 160 sales people wanted a self-improvement course. The groups are assumed to be independent random samples. Let straight pi subscript 1 space and space straight pi subscript 2 represent the true proportion of workers who would like to attend a self-improvement course in the recent study and the past study respectively. What is the value of the test statistic to use in evaluating the alternative hypothesis that there is a difference in the two population proportions using alpha equals 0.10

The calculated Z = 1.2 < 1.645 at  0.1 level of significance

Null hypothesis is accepted

There is a no difference in the two population proportions using alpha equals 0.10

Step-by-step explanation:

Given first sample size n₁ = 150

Given first sample proportion p₁ =  0.66

Given second sample size n₂ = 160

Given second sample proportion p₂ =  0.60

Null hypothesis :H₀: p₁ =  p₂

Alternative Hypothesis: H₁:p₁ ≠  p₂

Test statistic

Where

Q = 1- P = 1- 0.629 = 0.371

Z = 1.2

Level of significance  ∝=0.1

The critical value at ∝=0.1

The calculated Z = 1.2 < 1.645 at  0.1 level of significance

Null hypothesis is accepted

There is a no difference in the two population proportions using alpha equals 0.10

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.