Triangles CBA and CED are similar. AB is parallel to DE.

AB = 9cm, BE = 4.8cm, EC = 6cm and ED = k cm.

Work out the value of k.

*see attachment below for the figure being referred

k = 5cm

Step-by-step explanation:

==>Given:

∆CBA ~ ∆CED

Side lengths of ∆CBA:

BC = BE + EC = 4.8 + 6 = 10.8 cm

AB = 9cm

Side lengths of ∆CED:

EC = 6cm

ED = k

==>Required:

Value of k

==>Solution:

Since ∆CBA ~ ∆CED, the ratio of their corresponding besides would be the same, with same proportion.

Thus,

AB/ED = BC/EC

9/k = 10.8/6

Cross multiply to find the value of k

9 × 6 = 10.8 × k

54 = 10.8 × k

Divide both sides by 10.8

54/10.8 = k

5 = k

k = 5cm

d. is the correct answer

step-by-step explanation:

squares, rhombus, rectangles