There is a bag filled with 4 blue, 3 red and 5 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting 2 greens?

The probability of getting 2 greens is 5/31

Probability is the likelihood or chance that an event will occur. It is expressed as:

Probability = Expected outcome/Total outcome

Given that a bag is filled with 4 blue, 3 red and 5 green marbles, the total outcome is expressed as:

If green is picked at first, the probability of selecting a green is  5/12

The probability of getting 2 greens = 5/12 × 4/11

The probability of getting 2 greens = 20/132

The probability of getting 2 greens = 5/31

Hence the probability of getting 2 greens is 5/31

Learn more here: link

The answer would be just about 61% or 9/14

Step-by-step explanation:

So, it would be a 71% chance to get 1 green out of the bag, but then you have to keep that green out, which then lowers the chances of getting another green out of the bag, then you have to combine the percentages, and then that is the final percentage.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

probability for j is 1/4

while

a is 1/6