Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, h greater-than-or-equal-to 0 with d being the distance they can see in miles and h being their eye-level height in feet. StartRoot 5 EndRoot mi

3 StartRoot 5 EndRoot mi

15 StartRoot 5 EndRoot mi

45 StartRoot 5 EndRoot mi

The answer is 3√5 mi.

The formula is: d = √(3h/2)

Wyatt:

h = 120 ft

d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?

Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi

its b

Step-by-step explanation:

i just did it

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

you cant answer this dummy

step-by-step explanation: