Four different positive integers have a product of 110.
What is the sum of the four integers?

Given:

Four different positive intergers as a product of 110

To find:

The sumnof the four numbers whose product is 110

Solution:

1) To find the number we have to find the prime factorization of the given number 110

2) Prime factorization of 110 is

110 = 1×2 × 5 = 11

3) So the four numbers whose product is 110 are 1,2,5 and 11

4) The sum of number's are

1+2+5+11=19

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i