Two roots of a 3-degree polynomial equation are 5 and -5. Which of the following cannot be the third root of the equation ? 0
-5i
-5
5i
5

- 5i and 5i

Step-by-step explanation:

The Fundamental theorem of Algebra states that a polynomial of degree 3 has 3 roots, real and/ or complex.

Complex roots occur in conjugate pairs.

Given 2 real roots x = 5, x = - 5

There cannot be complex roots as they occur in pairs which would result in the polynomial having 4 roots instead of 3.

x = -2

y = 848

step-by-step explanation:

plug in the numbers

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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