Given a square with two vertices of one side located at -5,-3 and -5,12 in square units what is its area

Step-by-step explanation:

Lets find the distance (the side length of the square)

D=sqrt((x2-x1)^(2)+(y2-y1)^(2))

plug in the coordinates:

D=sqrt((-5-(-5))^(2)+(12-(-3))^(2))

D=sqrt(0^(2)+15^(2))

D=sqrt(15^(2))

D=15

Area of a square is side length squared

A=s^2

A=15^2

A=225 units squared

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

can you rephrase the question ? it is unclear : -)

step-by-step explanation: