Use reduction of order (NOT the integral formula we developed) to find the general solution of the nonhomogeneous linear DE, showing all work. Also clearly state the particular solution yp that you obtain using the reduction of order process and show a clear check that your particular solution yp satisfies the original nonhomogeneous DE. [Do NOT use the Method of Undetermined Coefficients here!] ''y + 6y' + 9y + 4e^x
Note: Use the characteristic polynomial to find a first solution yi of the associated homogencous DE.)

where A,B are constants.

Step-by-step explanation:

Consider the differential equation . To find the homogeneus solution, we assume that and replace it in the equation . If we do so, after using some properties of derivatives and the properties of the exponential function we end up with the equation

which leads to r = -3. So, one solution of the homogeneus equation is , where c_1 is a constant.

To use the order reduction method, assume

where v(x) is an appropiate function. Using this, we get

Plugging this in the original equation we get

re arranging the left side we get

Since y is a solution of the homogeneus equation, we get that . Then we get the equation

We can change the variable as w = v' and w' = v'', and replacing y with y_h, we get that the final equation to be solved is

Or equivalently

By integration on both sides, we get that w = e^{4x}+ k[/tex] where k is a constant.

So by integration we get that v = where d is another constant.

Then, the final solution is

where A,B are constants

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube