I am thinking of 3 consecutive numbers less than 100.The first number has 5 as one of its factors, the second number has 1 as its factors and the last number has 2 a one of its factors

10, 11 and 12.

Step-by-step explanation:

A number has 5 as one of its factors, when last digit is 5 or 0. Only prime numbers have 1 as the only factor and a number has 2 as one of its factors when last digit is 2, 4, 6, 8 or 0.

Three possible consecutive numbers are 10, 11 and 12. 10 is the product of 2 and 5, 11 is a prime number and 12 is the product of 3 and 2². Therefore, possible choice is 10, 11 and 12.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°