Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, -3) y = 2x – 21

y = -2/3x +3

Step-by-step explanation:

2x + 3y = 5

First we need to find the slope of this line by subtracting 2x

3y = -2x +5

Divide by 3

3y/3 = -2/3x +5/3

y = -2/3x +5/3

The slope is -2/3

Parallel lines have the same slope

We have the point (9,-3)

y = mx+b

where m is the slope and b is the m intercept

y = -2/3x+b

-3 = -2/3(9) +b

-3 = -6+b

-3+6 = -6+6+b

3 = b

y = -2/3x +3

y= -2/3x+3

Step-by-step explanation:

Given line:

Parallel line has the same slope and equation is:

using the given point (9, -3) we can find y-intercept:

So the required equation is:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a