The 20 to 34 age groups are approximately normally distributed with µ = 110

21.94% of people aged 20 to 34 have IQs between 125 and 150.

Step-by-step explanation:

The complete question is: Scores on the Wechsler Adult Intelligence Scale (a standard IQ test) for the 20 to 34 age group are approximately Normally distributed with  μ = 110  and  σ = 25.

What percent of people aged 20 to 34 have IQs between 125 and 150?

Let X = Scores on the standard IQ test for the 20 to 34 age group

SO, X ~ Normal()

The z-score probability distribution for the normal distribution is given by;

                            Z  =    ~ N(0,1)

where, = population mean = 110

            = standard deviation = 25

Now, the percent of people aged 20 to 34 have IQs between 125 and 150 is given by = P(125 < X < 150) = P(X < 150) - P(X 125)

       P(X < 150) = P( < ) = P(Z < 1.60) = 0.9452

       P(X 125) = P( ) = P(Z 0.60) = 0.7258

The above probability is calculated by looking at the value of x = 1.60 and x = 0.60 which has an area of 0.9452 and 0.7258.

Therefore, P(125 < X < 150) = 0.9452 - 0.7258 = 0.2194 or 21.94%

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

answer: 8

step-by-step explanation: