What is f(x)=x3+2x2−5x−6 in factored form given that 2 is a zero of the function?

Since 2 or x-2= 0 is a zero of the function we divide it by the function to get the other factors

x³ + 2x² - 5x - 6 ÷ x -2

We get

(x + 3)(x+1) = 0

Therefore x³ + 2x² - 5x - 6 in factored form is

(x - 2)(x + 3)(x + 1)

Hope this helps.

the answers c

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3