A company has 3 positions(President, VP, manager) to fill. If there are 15 candidates, how many outcomes are possible?

455 possible outcomes

Step-by-step explanation:

If there are 3 positions and 15 candidates, you multiply 15 by 14, then by 13 to get the number of possible outcomes times 6.

This is because once a candidate gets a position, there will be 1 less candidate without a position each time.

15 * 14 * 13 = 2,730

Now, since there are only 3 positions, the first position has 3 possible ways, the second position has 2 possible ways, and the third position has 1 possible way.

3 * 2 * 1 = 6

2,730 / 6 = 455

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation:

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4