Given that angle ABC=65° and angle BCD=105°. Is it possible (consider all cases): that a)Line AB is parallel to line CD. and b) Line AB is parallel to line CD.

  No

Step-by-step explanation:

With the given angle measures, the angle between AB and CD is either 10° or 40°. AB and CD cannot be parallel.

No

Step-by-step explanation:

Since BC is common line section, in order to have AB parallel to CD, angles ABC and BCD must be equal.

As ∠ABC ≠ ∠BCD AB and CD can not be parallel

The answer is no

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}