Identify any solutions to the system given below. 2х + y = 5
Зу = 15 – 6х
(6, -7)
(2, 1)
(-2, -9)
(-4, 13)
ООО

• (6, -7)
• (-4, 13)

Explanation:

• Option One

2x + y = 5
2(6) + (-7) = 5
12 - 7 = 5
5 = 5 {true}

3y = 15 - 6x
3(-7) = 15 - 6(6)
-21 = 15 - 36
-21 = -21 {true}

• Option Two

2x + y = 5
2(2) + 1 = 5
4 + 1 = 5
5 = 5 {true}

3y = 15 - 6x
3(1) = 15 - 6(2)
3 = 15 - 12
3 = 13 {not true}

• Option Three

2x + y = 5
2(-2) + (-9) = 5
-4 - 9 = 5
-13 = 5 {not true}

3y = 15 - 6x
3(-9) = 15 - 6(-2)
-27 = 15 + 12
-27 = 27 {not true}

• Option Four

2x + y = 5
2(-4) + 13 = 5
-8 + 13 = 5
5 = 5 {true}

3y = 15 - 6x
3(13) = 15 - 6(-4)
39 = 15 + 24
39 = 39 {true}

(6, -7)

(2, 1)

(-4, 13)

Step-by-step explanation:

2х + y = 5  ⇒ y= 5-2x

Зу = 15 – 6х ⇒ y= 5-2x

Both equations are same so any point satisfying one of them is the solution.

(6, -7)

-7= 5-12 - yes

(2, 1)

1= 5- 4 - yes

(-2, -9)

-9= 5 + 4 - no

(-4, 13)

13= 5+8- yes

So 3 of given points satisfy the equation