Find the derivative of g(t)=3t^2+2t at t=-1 algebraically

8.

Step-by-step explanation:

If y = ax^n then the derivative y' = anx^(n-1)

g(t) = 3t^2 + 2t so  the derivative g'(t)

2*3 t^(2-1) + 2t(1-1)

= 6t + 2

At t =1 its value is  6 + 2 = 8.