One ticket is selected at random from 100 tickets numbered 00,01,02,0399. Suppose x is the sum of digits and y is the product of the digits. then the probability that x=9 and y=0 is?

N ( s ) = 100

Y = { 01 , 02 ,03 ,04 ,05 , 06 ,07 , 08 , 09 , 10 , 20 ,30 , 40 ,50 , 60 ,70 ,80 , 90 }

so

n ( y ) = 18

P ( y ) = n ( y ) / n ( S )

= 18 /100

= 9 /50

x = { 09 , 18 , 27 , 36 , 45 , 54 , 63 , 72 , 81 , 90 }

n ( x ) = 10

P ( x ) = n ( x ) / n ( s )

= 10 / 100

= 1 / 10

so probability of event x is 1/10 and event y is 9/50

i think the answer is b.

step-by-step explanation:

not 100% sure though.