F(x) 5,450(1.024)^x The domain for the function that represents the amount of time the money will be in the college fund is _ the range for the function that represents the amount of money that is in the college fund is _

1.) Domain X = all positive real numbers

2.) Range: F(x) > = 5450

Step-by-step explanation:

Given that

F(x) = 5,450(1.024)^x

Where the domain is the independent variable X and the range is the dependent variable Y or F(x)

Since the domain for the function represents the amount of time the money will be in the college fund, time cannot be negative, it will always be positive.

Therefore, domain x will be all positive real numbers.

The least domain x = 0

Substituting domain into the equation will give us a range of value:

F(x) = 5450 × ( 1.024 )^0

F(x) = 5450 × 1

F(x) = 5450

That is, the least value of range = 5450

Therefore, Range will be F(x) greater than or equal to 5450.

F(x) > = 5450

a. is correct

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!