(05.01 MC) In triangle JKL, tan(b°) = three fourths and cos(b°) =four fifths. If triangle JKL is dilated by a scale factor of one half, what is sin(b°)? PLEASE HELP! triangle KL in which angle K is a right angle and angle L measures b degrees sin(b°) = three fifths sin(b°) = four fifths sin(b°) = five thirds sin(b°) = five fourths

Step-by-step explanation:

We are given a where

As per trigonometric rules,

Comparing the given value of tangent and cosine:

Perpendicular = 3 units

Base = 4 units

Hypotenuse = 5 units

Also, we know that:

Now, it is given that the triangle is dilated by a scale factor of .

i.e. all the sides will become half of its initial values.

New Perpendicular = 1.5 units

New Base = 2 units

New Hypotenuse = 2.5 units

Using the formula for sine:

answer: 48

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step-by-step explanation: