Write an equation for a polynomial function that has the given roots

-2. 3i , and 5

x^4 - 3x^3 - x^2 - 27x - 90 = 0.

Step-by-step explanation:

If 3i is one root then another is -3i.

In factor form we have:

(x + 2)(x - 5)(x - 3i)(x + 3i) = 0

(x^2 - 3x - 10)(x^2 -9i^2) = 0

(x^2 - 3x - 10)(x^2 + 9) = 0

x^4 + 9x^2 - 3x^3 - 27x - 10x^2 - 90 = 0

x^4 - 3x^3 - x^2 - 27x - 90 = 0.

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

copyright potato 2019.

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5