A rope is cut into three pieces of different lengths. The first piece is of length x meters, The length of the second piece is 2 meters more than twice the length of the first piece. The length of the third piece is thrice the length of the second piece. Pls answer fast pls pls pls pls pls pls pls

first piece = 5 m

second piece = 2(5) + 2 = 12 m

third piece = 3(2x + 2) = 6(5) + 6 = 36 m

Step-by-step explanation:

The question is incomplete, the length of the actual rope is unknown but it should be given . Let us assume the length of the rope is 53 meters.

The rope is cut into 3 pieces of different length.

first piece = x

second piece = 2x + 2

third piece = 3(2x + 2) = 6x + 6

Since the length of the actual rope is assumed to be 53 meters .The length of the first piece, second piece and third piece can be calculated as follows.

we add the length of the pieces to get the actual length of each piece. Therefore,

x + 2x + 2 + 6x + 6 = 53

collect like terms

9x + 8 = 53

9x = 53 - 8

9x = 45

x = 45/9

x = 5 meters

first piece = 5 m

second piece = 2(5) + 2 = 12 m

third piece = 3(2x + 2) = 6(5) + 6 = 36 m

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b