A square pyramid is made up of a base with a side length of 10 inches and faces that are triangles with a height of 12 inches. What is the surface area of the square pyramid? A. 120 square inches

B. 125 square inches

C. 240 square inches

D. 340 square inches

The correct option is D

D) 340 inch²

Step-by-step explanation:

The base of the pyramid is a square with side 10 inch

Area of square base = Length · Width = 10 · 10

Area of square base = 100 inch²

Height of triangle = 12 inches

Base of triangle = 10 inches

Area of triangle = (1/2)(Height)(Base) = (1/2)(12)(10)

Area of triangle = 60 inch²

Total number of triangles in a pyramid = 4

Total Area of 4 triangles = 4 · 60 inch²

Total Area of 4 triangles = 240 inch²

Surface Area = Area of 4 triangle + Area of the square base

Surface Area = 240 inch² + 100 inch²

Surface Area = 340 inch²

The Answer would be D

Step-by-step explanation:

This Answer would also apply to E2020 test/exam

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.