I promise I will mark as brainiest and 5 stars and thanks a snake saw a hawk at height of 160 meter and hawk was flying at a speed of 24meters/minute to pounce on it if the hawk is launching vertically downwards according to the relation d=Vt+4.9t^{2} where d is the distance by meter, V is the launching speed in meter/minute and t is the time in minutes find the time the snake takes to escape before the hawk reaches it

3.77min

Step-by-step explanation:

we are given the relationship:

d = Vt + 4.9t²,

where

d = distance in meters = given as 160m

V = launching (aka initial) speed = 24m/min

t = time in min (we are asked to find this)

if we subsititute the above values into the equation:

d = Vt + 4.9t²

160 = 24t + 4.9t²

4.9t² + 24t - 160 = 0  (we simply solve for t)

Using the quadratic formula:

t = { -24 ± √[24² - (4)(4.9)(-160]  } / [(2)(4.9)]  }

t = 3.77 min or -8.67 min  

because time cannot be negative in this case, we pick the positive number.

t = 3.77min

srry ask agian

step-by-step explanation: