On a particular night, a baseball stadium sells 60% of its seats, and of those, 15% do not end up showing up to the game. Assuming everyone present is sitting in a seat, what percentage of seats in the stadium are empty?

Step-by-step explanation:

so llets find what 15% of 60% really is,

0.15*0.60=0.09

0.09 AKA 9%

so since 9% of people didn't show up we can subtract 9% from 60%

so 60-9=51

51% of setas are taken

to find the percent of seats still empty, subtract 100 form 51

so

100-51=49

49% of seats are still empty

Hope this helsp!

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