The table below shows student's preferred European football clubs as indicated in a survey run by their math teacher. If two students were selected without replacement at random, what is the
probability that the first and second students prefer Juventus?

Option D. 91/4950

Step-by-step explanation:

The following data were obtained from the question:

Barcelona (B) = 23

Real Madrid (R) = 23

Liverpool (L) = 22

Manchester City (M) = 18

Juventus (J) = 14

Total (T) = 100

Next, we shall determine the probability of the first pick i.e probability of Juventus. This is illustrated below:

P(J1) = n(J) /n(T)

P(J1) = 14/100

Now, the picking is done without replacement. The next pick being Juventus will reduce in number and likewise the total number will also reduce i.e

Juventus = 13

Total = 99

Therefore, the probability that the 2nd pick is Juventus is given below:

P(J2) = 13/99

Now, we can obtain the probability that the 1st and 2nd student prefer Juventus as follow:

P(J1 and J2) = P(J1) x P(J2)

P(J1) = 14/100

P(J2) = 13/99

P(J1 and J2) = P(J1) x P(J2)

P(J1 and J2) = 14/100 x 13/99

P(J1 and J2) = 7/50 x 13/99

P(J1 and J2) = 91/4950

Therefore, the probability that the 1st and 2nd student prefer Juventus is 91/4950

yes

step-by-step explanation:

give me the question

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step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3