What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (-5, 1)? Check all that apply.
Oy=-x-1
2x + 5y = -5
Oy=-x-3
2x + 5y = -15
y - 1=-2/5(x+ 5)

B, E

Step-by-step explanation:

The equation of that line in slope intercept form is y = -2/5x + 2

The slope of a line parallel to that line will be the same as its slope, so -2/5.

To find the y-intercept of a line that passes through the point (-5, 1) with that slope, you will have to plug in the x and y values of that point into what you know of the equation of the line.

y = -2/5x + b

1 = -2/5(-5) + b

1 = 2 + b

-1 = b

From this, you can construct an equation.

y = -2/5x - 1

However, this is not an answer choice.  

It cannot be A because this line does not have a slope of -1.

2x + 5y = 15

5y = -2x - 5

y = -2/5x - 1

It can be B because this line is the same as the equation we came up with.

It cannot be C because this line does not have a slope of -1 or a y-intercept of -3.

2x + 5y = -15

5y = -2x - 15

y = -2/5x - 3

It cannot be D because this line does not have a y-intercept of -3.

y - 1 = -2/5(x + 5)

y - 1 = -2/5x - 2

y = -2/5x - 1

It can be E because this equation matches the one we came up with.

A: y = -2/5x - 1

B: 2x + 5y = -5

E: y - 1 = -2/5(x+5)

Step-by-step explanation:

I only got 2 out of 3 answers, but the ones listed above should be correct :) Hope this helps! :D

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

answer: it's d

step-by-step explanation: