PLEASE HELP Here's a graph of a linear function. Write the
equation that describes that function.

y = 2/3x + 1

Step-by-step explanation:

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

The line is rising from left to right, so the slope will be positive. When you count rise over run, you get 2/3. (start at the y-intercept, count up until the line goes through the corner of a square, and then count over to that point. It's faster than using the slope formula)

y = 2/3x + b

The line intersects the y-axis at 1, so y = 2/3x + 1.

I hope this helps :)

y=2/3 x +b

Step-by-step explanation:

y=mx+b

take two points (0,1) and (3,3) from the graph

m=y2-y1/x2-x1

m=2/3

when x=0 then y=b

the equation is y=2/3 x+1

answer:

idk

step-by-step explanation:

391.6 is the correct answer