Assume that when adults with smartphones are randomly selected, 49% use them in meetings or classes. If 30 adult smartphone users are randomly selected, find the probability that exactly 23 of them use their smartphones

0.0013684

Step-by-step explanation:

Given the following :

Probability (p) = 49% = 0.49

Number of selected adults (n) = 30

Find the probability that exactly 23 use their smartphone.

The problem is abive can be solved using the binomial probability function.

Binomial probability :

P(X = x) = [n! / x! (n-x)!] * P^x * (1 - P)^(n-x)

At x = 23

P(X = 23) = [30! / 23! (30-23)!] * P^23 * (1-0.49)^(30-23)

P(X = 23) = [30! / 23! (7)!] * 0.49^23 * (0.51)^7

P(X =23) = (2035800) × 6.72203E−10

= 0.0013684

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: