A coconut is a fruit that is made up of a hard outer shell that is spherical. Inside, there is a thick layer of coconut meat that forms another spherical shell around the coconut milk. If the diameter of an entire coconut is 5 inches, and the coconut meat is 1 inch thick, then there is room for approximately _[blank]_ in3 of coconut milk. What number correctly fills in the blank in the previous sentence? Hint: Find the radius of the inside sphere and use that to calculate the volume. Use 3.14 for π and round your answer to the nearest hundredth, if necessary, like this: 42.53 PLEASE HELP!!!

do your own work and don"t cheat.

step-by-step explanation:

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step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

we would need a picture of the quadrilateral in order to answer the question. also, it seems that the question is missing some components.