Mathematics, 26.06.2020 15:01 ashleyjohnson2002
1.-3=-212+ 2x
2 -3=-202Β² β 2)
3 -3+ β 2 v=-2012 - x + 12v)
I = -2(x - 2)2
5. I = (-
The two solutions are
+
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1.-3=-212+ 2x
2 -3=-202Β² β 2)
3 -3+ β 2 v=-2012 - x + 12v)
I = -2(x - 2)2
5. I...
3 -3+ β 2 v=-2012 - x + 12v)
I = -2(x - 2)2
5. I...
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