Consider a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year. For simplicity, assume that there is a 50% probability that after the accident the car will need repairs costing $500, a 40% probability that the repairs will cost $5,000, and a 10% probability that the car will need to be replaced, which will cost $15,000. What is the expected loss for the car owner per year

The expected loss for the car owner per year is $750.

Step-by-step explanation:

We are given that a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year.

Let X = Loss for the particular year for a car owner

Now as we know that the loss to the car owner may be of $0, $500, $5,000 or $15,000 because these amount he has to pay as a part of repair cost if his car met with an accident.

So, the probability distribution of X is given by;

           X (Amount of Loss)                               P(X)

                     $0                                                      0.80

                      $500                                            (0.20)(0.50) = 0.10

                      $5,000                                         (0.20)(0.40) = 0.08

                      $15,000                                        (0.20)(0.10) = 0.02

                       Total                                                         1                    

Here, the probability of (0.20)(0.50) means that for the loss of $500, first the car must have to met with an accident and then there is 50% chance that after the accident the car will need repairs costing $500.

Now, the expected loss for the car owner per year is  =

     =  

                           =  50 + 400 + 300 = $750.

So, the expected loss for the car owner per year is $750.

ian gonna lie that is way to much

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step-by-step explanatio89