The estimated probability of a football player scoring a touchdown during a particular game is 39%. Of several simulations of the foot ball player playing two games were performed, in what percentage of the simulations would the football player be most likely to get a touchdown in each of the two games?

The percentage of the simulations of two games that the football player would most likely get a touchdown in each of the two games = 15.21%

Step-by-step explanation:

The probability of scoring a touchdown in one game for the football player = 39% = 0.39

Probability of scoring a touchdown in each of the two consecutive games = (Probability of scoring a touchdown in the first game) × (Probability of scoring a touchdown in the second game)

Since the probability of scoring a touchdown in each game the football player plays in is independent of one another.

Probability of scoring a touchdown in the first game = Probability of scoring a touchdown in the second game = 0.39

Probability of scoring a touchdown in each of the two consecutive games = 0.39 × 0.39 = 0.1521

If 100 simulations of the two games are made, the player scores in each of the two games in 15.21 of them, hence, the percentage of the simulations that the football player would most likely get a touchdown in each of the two games = 15.21%

Hope this Helps!!

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm